Math problem

37 chief

Well-known Member
I am setting up a temporary holding tank for my fish while I make a repair to the pond liner. I have a stock watering tank that is 5 1/2 feet across, and 2 ft deep. Hoe many gallons will it hold? I have a couple free Koy if anyone wants them. Stan
 
About 356.2 gallons if it is a round tank and I didn't make any mistakes...

Lets see what others come up with..
 
You probably already know this, but best to use the pond water, the same water they are used to being in.

The next big city north of here, they had a huge Japanese garden display with thousands of Koy (I call them carp). They needed to drain the system for repairs, so they moved the fish to a tank...

Filled with chlorinated city water! Oops...

Some were rumored to have been 100+ years old!
 
Volume equals l x w x h. Length width height. Thats for a square or rectangle. Not a cylinder. Wingnut
 
You may not want to fill the tank all the way to the top or some of the fish will jump out, BTDT. A hard cover works too.
 
if its a cylinder---3.14159 (5.5)(5.5) (1/4) (x2)= CF and 7.48 gal/CF----gives the number of gallons= 375
 
Hmmm, let's see, using pi x r x r x h gives me this calculation ....

3.14 x 0.837m x 0.837m x 0.6m = 1.32 cubic meters of water OR if you like, 1,320 litres. Sooooo easy when you use metric ..... LOL.
 
We used to have Koi, however the Herons found our pond, so now it is water lilies and frogs.
 
Volume equals l x w x h. Length width height. Thats for a square or rectangle. Not a cylinder. Wingnut
 

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