Width of cut (in inches) X ground speed (mph) divide by 100 = acres per hr.
Don't just use the width of the mower, but actual cutting width. You'll have some overlap. A 60" mower generally isn't cutting a full 60". You'll probably average around 50" to 55" of actualy cut width.
Loss of efficiency due to turns, dodging obstructions, ect....100 is max efficiency. If you estimate loss of efficiency @ 10%, divide by 110....20%, 120...and so on.
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