Posted by 440roadrunner on April 28, 2009 at 14:43:44 from (98.145.76.31):
In Reply to: Electric math problem posted by jdemaris on April 28, 2009 at 13:30:21:
Just a few ramblings in general
Be very careful about efficiency. I haven't tested this, but you can, I think. The draw of the refer unit may well be different on the inverter because of differences in sine wave purity, actual output voltage, etc. so you need to measure that under those conditions, and average over probably several days
Also, The starting load may affect the amp hours rating somewhat, especially if for some reason the thing short cycles I can imagine that inverter "droop" could cause significant higher starting loads on the inverter than on goo solid AC, especially if the batteries are down.
Last is your amp-hour rating. What conditions are those batteries rated for, I.E, the old so called "20 hour" rating? You DO realize that you cannot simply use the mathematical product of an amp hour rating and come up with the true capacity? That is, these ratings are sort of averaged at best, a guesstimate in the middle, and sometimes an outright lie by the battery supplier at worst.
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